Why does low impedance require more current in a pacemaker?
This is based on the fundamental principle of Ohm’s Law:
Current (I) = Voltage (V) / Resistance (R)
In pacemakers, resistance is expressed as impedance (Z), which accounts for both resistive and reactive properties at the electrode-tissue interface.
Suppose the pacemaker delivers a voltage of 3.5 V. Here's how current changes with impedance:
Impedance (Z) | Current (I = V / Z) |
---|---|
600 Ω | 5.83 mA |
300 Ω | 11.67 mA |
So when impedance drops from 600 Ω to 300 Ω, the required current doubles — even though voltage remains the same.
Over time, the body may form a fibrotic capsule around the device electrode, which raises impedance — sometimes improving efficiency and extending battery life slightly.
Low impedance → higher current → greater battery consumption. This is a key factor in pacemaker energy modeling.